Medium MCQ +4 / -1 PYQ · JEE Mains 2024

Consider the system of linear equations $x+y+z=4 \mu, x+2 y+2 \lambda z=10 \mu, x+3 y+4 \lambda^2 z=\mu^2+15$ where $\lambda, \mu \in \mathbf{R}$. Which one of the following statements is NOT correct ?

  1. A The system has unique solution if $\lambda \neq \frac{1}{2}$ and $\mu \neq 1,15$
  2. B The system has infinite number of solutions if $\lambda=\frac{1}{2}$ and $\mu=15$
  3. C The system is consistent if $\lambda \neq \frac{1}{2}$
  4. D The system is inconsistent if $\lambda=\frac{1}{2}$ and $\mu \neq 1$ Correct answer

Solution

<p>$x+y+z=4 \mu, x+2 y+2 \lambda z=10 \mu, x+3 y+4 \lambda{ }^2 z=\mu^2+15$,</p> <p>$$\Delta=\left|\begin{array}{ccc} 1 & 1 & 1 \\ 1 & 2 & 2 \lambda \\ 1 & 3 & 4 \lambda^2 \end{array}\right|=(2 \lambda-1)^2$$</p> <p>For unique solution $\Delta \neq 0,2 \lambda-1 \neq 0,\left(\lambda \neq \frac{1}{2}\right)$</p> <p>Let $\Delta=0, \lambda=\frac{1}{2}$</p> <p>$$\begin{aligned} & \Delta_y=0, \Delta_x=\Delta_z=\left|\begin{array}{ccc} 4 \mu & 1 & 1 \\ 10 \mu & 2 & 1 \\ \mu^2+15 & 3 & 1 \end{array}\right| \\ & =(\mu-15)(\mu-1) \end{aligned}$$</p> <p>For infinite solution $\lambda=\frac{1}{2}, \mu=1$ or 15</p>

About this question

Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations

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