Medium MCQ +4 / -1 PYQ · JEE Mains 2020

Let $\theta = {\pi \over 5}$ and $$A = \left[ {\matrix{ {\cos \theta } & {\sin \theta } \cr { - \sin \theta } & {\cos \theta } \cr } } \right]$$.

If B = A + A4 , then det (B) :

  1. A lies in (1, 2) Correct answer
  2. B lies in (2, 3).
  3. C is zero.
  4. D is one.

Solution

$$A = \left[ {\matrix{ {\cos \theta } &amp; {\sin \theta } \cr { - \sin \theta } &amp; {\cos \theta } \cr } } \right]$$ <br><br>A<sup>2</sup> = $$\left[ {\matrix{ {\cos \theta } &amp; {\sin \theta } \cr { - \sin \theta } &amp; {\cos \theta } \cr } } \right]$$$$\left[ {\matrix{ {\cos \theta } &amp; {\sin \theta } \cr { - \sin \theta } &amp; {\cos \theta } \cr } } \right]$$ <br><br>$\Rightarrow$ A<sup>2</sup> = $$\left[ {\matrix{ {\cos 2\theta } &amp; {\sin 2\theta } \cr { - \sin 2\theta } &amp; {\cos 2\theta } \cr } } \right]$$ <br><br>Similarly, A<sup>n</sup> = $$\left[ {\matrix{ {\cos n\theta } &amp; {\sin n\theta } \cr { - \sin n\theta } &amp; {\cos n\theta } \cr } } \right]$$ <br><br>$\therefore$ B = A + A<sup>4</sup> <br><br>= $$\left[ {\matrix{ {\cos \theta } &amp; {\sin \theta } \cr { - \sin \theta } &amp; {\cos \theta } \cr } } \right]$$ + $$\left[ {\matrix{ {\cos 4\theta } &amp; {\sin 4\theta } \cr { - \sin 4\theta } &amp; {\cos 4\theta } \cr } } \right]$$ <br><br>= $$\left[ {\matrix{ {\cos 4\theta + \cos \theta } &amp; {\sin 4\theta + \sin \theta } \cr { - \sin 4\theta - \sin \theta } &amp; {\cos 4\theta + \cos \theta } \cr } } \right]$$ <br><br>detB = (cos4$\theta$ + cos$\theta$)<sup>2</sup> + (sin4$\theta$ + sin$\theta$)<sup>2</sup> <br><br>= cos<sup>2</sup>4$\theta$ + cos<sup>2</sup>$\theta$ + 2cos4$\theta$ cos$\theta$ <br>+ sin<sup>2</sup>4$\theta$ + sin2$\theta$ + 2sin4$\theta$ –sin$\theta$ <br><br>= 2 + 2 ( cos4$\theta$ cos$\theta$ + sin4$\theta$ sin$\theta$) <br><br>$\Rightarrow$ detB = 2 + 2 cos3$\theta$ <br><br>at $\theta$ = ${\pi \over 5}$ <br><br>detB = 2 + 2cos ${{3\pi } \over 5}$ <br><br> = 2(1 - sin18) <br><br>= 2(1 - ${{\sqrt 5 - 1} \over 4}$) <br><br>= 2$\left( {{{5 - \sqrt 5 } \over 4}} \right)$ <br><br>= ${{{5 - \sqrt 5 } \over 2}}$ $\simeq$ 1.385 <br><br>$\therefore$ detB $\in$ (1, 2)

About this question

Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations

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