Medium INTEGER +4 / -1 PYQ · JEE Mains 2024

Let for any three distinct consecutive terms $a, b, c$ of an A.P, the lines $a x+b y+c=0$ be concurrent at the point $P$ and $Q(\alpha, \beta)$ be a point such that the system of equations

$$\begin{aligned} & x+y+z=6, \\ & 2 x+5 y+\alpha z=\beta \text { and } \end{aligned}$$

$x+2 y+3 z=4$, has infinitely many solutions. Then $(P Q)^2$ is equal to _________.

Answer (integer) 113

Solution

<p>$\because \mathrm{a}, \mathrm{b}, \mathrm{c}$ and in A.P</p> <p>$\Rightarrow 2 b=a+c \Rightarrow a-2 b+c=0$</p> <p>$\therefore \mathrm{ax}+\mathrm{by}+\mathrm{c}$ passes through fixed point $(1,-2)$</p> <p>$\therefore \mathrm{P}=(1,-2)$</p> <p>For infinite solution,</p> <p>$$\begin{aligned} & D=D_1=D_2=D_3=0 \\ & D:\left|\begin{array}{lll} 1 & 1 & 1 \\ 2 & 5 & \alpha \\ 1 & 2 & 3 \end{array}\right|=0 \\ & \Rightarrow \alpha=8 \\ & D_1:\left|\begin{array}{lll} 6 & 1 & 1 \\ \beta & 5 & \alpha \\ 4 & 2 & 3 \end{array}\right|=0 \Rightarrow \beta=6 \\ & \therefore Q=(8,6) \\ & \therefore Q^2=113 \end{aligned}$$</p>

About this question

Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations

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