Let $$A = \left[ {\matrix{ x & y & z \cr y & z & x \cr z & x & y \cr } } \right]$$, where x, y and z are real numbers such that x + y + z > 0 and xyz = 2. If ${A^2} = {I_3}$, then the value of ${x^3} + {y^3} + {z^3}$ is ____________.
Answer (integer)
7
Solution
$$A = \left[ {\matrix{
x & y & z \cr
y & z & x \cr
z & x & y \cr
} } \right]$$
<br><br>$\therefore$ $|A| = \left( {{x^3} + {y^3} + {z^3} - 3xyz} \right)$<br><br>Given ${A^2} = {I_3}$<br><br>$|{A^2}| = 1$<br><br>$\therefore$ ${({x^3} + {y^3} + {z^3} - 3xyz)^2} = 1$<br><br>$\Rightarrow {x^3} + {y^3} + {z^3} - 3xyz = 1$ only as $(x + y + z > 0)$<br><br>$\Rightarrow {x^3} + {y^3} + {z^3} = 6 + 1 = 7$
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
This question is part of PrepWiser's free JEE Main question bank. 274 more solved questions on Matrices and Determinants are available — start with the harder ones if your accuracy is >70%.