Let $A$ be a $3 \times 3$ matrix of non-negative real elements such that $$A\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]=3\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$$. Then the maximum value of $\operatorname{det}(\mathrm{A})$ is _________.
Answer (integer)
27
Solution
<p>Let $$A = \left[ {\matrix{
{{a_{11}}} & {{a_{12}}} & {{a_{13}}} \cr
{{a_{21}}} & {{a_{22}}} & {{a_{23}}} \cr
{{a_{31}}} & {{a_{32}}} & {{a_{33}}} \cr
} } \right]$$</p>
<p>Now</p>
<p>$$A\left[\begin{array}{l}
1 \\
1 \\
1
\end{array}\right]=3\left[\begin{array}{l}
1 \\
1 \\
1
\end{array}\right]$$</p>
<p>$$\left[ {\matrix{
{{a_{11}}} & {{a_{12}}} & {{a_{13}}} \cr
{{a_{21}}} & {{a_{22}}} & {{a_{23}}} \cr
{{a_{31}}} & {{a_{32}}} & {{a_{33}}} \cr
} } \right]\left[ {\matrix{
1 \cr
1 \cr
1 \cr
} } \right] = \left[ {\matrix{
3 \cr
3 \cr
3 \cr
} } \right]$$</p>
<p>$$\begin{aligned}
& a_{11}+a_{12}+a_{13}=3 \\
& a_{21}+a_{22}+a_{23}=3 \\
& a_{31}+a_{32}+a_{33}=3
\end{aligned}$$</p>
<p>Now for maximum value of $$\operatorname{det}(A)=a_{i j}\left\{\begin{array}{ll}0 & i \neq j \\ 3 & i=j\end{array}\right\}$$</p>
<p>$\therefore|A|=27$</p>
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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