Let A = [aij] and B = [bij] be two 3 × 3 real matrices such that bij = (3)(i+j-2)aji, where i, j = 1, 2, 3. If the determinant of B is 81, then the determinant of A is:
Solution
|B| = $$\left| {\matrix{
{{b_{11}}} & {{b_{12}}} & {{b_{13}}} \cr
{{b_{21}}} & {{b_{22}}} & {{b_{23}}} \cr
{{b_{31}}} & {{b_{32}}} & {{b_{33}}} \cr
} } \right|$$
<br><br>= $$\left| {\matrix{
{{3^0}{a_{11}}} & {{3^1}{a_{12}}} & {{3^2}{a_{13}}} \cr
{{3^1}{a_{21}}} & {{3^2}{a_{22}}} & {{3^3}{a_{23}}} \cr
{{3^2}{a_{31}}} & {{3^3}{a_{32}}} & {{3^4}{a_{33}}} \cr
} } \right|$$
<br><br>= $${3.3^2}\left| {\matrix{
{{a_{11}}} & {{3^1}{a_{12}}} & {{3^2}{a_{13}}} \cr
{{a_{21}}} & {{3^1}{a_{22}}} & {{3^2}{a_{23}}} \cr
{{a_{31}}} & {{3^1}{a_{32}}} & {{3^2}{a_{33}}} \cr
} } \right|$$
<br><br>= $${3.3^2}{.3.3^2}\left| {\matrix{
{{a_{11}}} & {{a_{12}}} & {{a_{13}}} \cr
{{a_{21}}} & {{a_{22}}} & {{a_{23}}} \cr
{{a_{31}}} & {{a_{32}}} & {{a_{33}}} \cr
} } \right|$$
<br><br>= 3<sup>6</sup>.|A|
<br><br>$\therefore$ 3<sup>6</sup>.|A| = 81
<br><br>$\Rightarrow$ |A| = ${1 \over 9}$
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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