If for the matrix, $$A = \left[ {\matrix{ 1 & { - \alpha } \cr \alpha & \beta \cr } } \right]$$, $A{A^T} = {I_2}$, then the value of ${\alpha ^4} + {\beta ^4}$ is :
Solution
$$\left[ {\matrix{
1 & { - \alpha } \cr
\alpha & \beta \cr
} } \right]\left[ {\matrix{
1 & \alpha \cr
{ - \alpha } & \beta \cr
} } \right] = \left[ {\matrix{
{1 + {\alpha ^2}} & {\alpha - \alpha \beta } \cr
{\alpha - \alpha \beta } & {{\alpha ^2} + {\beta ^2}} \cr
} } \right] = \left[ {\matrix{
1 & 0 \cr
0 & 1 \cr
} } \right]$$<br><br>1 + $\alpha$<sup>2</sup> = 1<br><br>$\alpha$<sup>2</sup> = 0<br><br>$\alpha$<sup>2</sup> + $\beta$<sup>2</sup> = 1<br><br>$\beta$<sup>2</sup> = 1<br><br>$\alpha$<sup>4</sup> = 0<br><br>$\beta$<sup>4</sup> = 1<br><br>$\alpha$<sup>4</sup> + $\beta$<sup>4</sup> = 1
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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