Let $A = \left[ {\matrix{ 2 & 3 \cr a & 0 \cr } } \right]$, a$\in$R be written as P + Q where P is a symmetric matrix and Q is skew symmetric matrix. If det(Q) = 9, then the modulus of the sum of all possible values of determinant of P is equal to :
Solution
$A = \left[ {\matrix{
2 & 3 \cr
a & 0 \cr
} } \right]$, ${A^T} = \left[ {\matrix{
2 & a \cr
3 & 0 \cr
} } \right]$<br/><br/>$A = {{A + {A^T}} \over 2} + {{A - {A^T}} \over 2}$<br/><br/>Let $P = {{A + {A^T}} \over 2}$ and $Q = {{A - {A^T}} \over 2}$<br/><br/>$$Q = \left( {\matrix{
0 & {{{3 - a} \over 2}} \cr
{{{a - 3} \over 2}} & 0 \cr
} } \right)$$<br/><br/>Det (Q) = 9<br/><br/>$0 - \left( {{{3 - a} \over 2}} \right)\left( {{{a - 3} \over 2}} \right) = 9$<br/><br/>$$ \Rightarrow {\left( {{{a - 3} \over 2}} \right)^2} = 9 \Rightarrow {(a - 3)^2} = 36$$<br/><br/>$a - 3 = \pm \,6 \Rightarrow a = 9, - 3$<br/><br/>$$P = \left[ {\matrix{
2 & {{{a + 3} \over 2}} \cr
{{{a + 3} \over 2}} & 0 \cr
} } \right]$$<br/><br/>$P = \left[ {\matrix{
2 & 6 \cr
6 & 0 \cr
} } \right]$ or $\left[ {\matrix{
2 & 0 \cr
0 & 0 \cr
} } \right]$
<br/><br/> | P | = - 36 or 0
<br/><br/>$\therefore$ | $-$36 + 0 | = 36
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
This question is part of PrepWiser's free JEE Main question bank. 274 more solved questions on Matrices and Determinants are available — start with the harder ones if your accuracy is >70%.