Let $A = [a_{ij}]$ be a $2 \times 2$ matrix such that $a_{ij} \in \{0, 1\}$ for all $i$ and $j$. Let the random variable $X$ denote the possible values of the determinant of the matrix $A$. Then, the variance of $X$ is:
Solution
<p>$$\begin{aligned}
& |A|=\left|\begin{array}{ll}
a_{11} & a_{12} \\
a_{21} & a_{22}
\end{array}\right| \\
& =a_{11} a_{22}-a_{21} a_{12} \\
& =\{-1,0,1\}
\end{aligned}$$</p>
<p>$$\begin{array}{c|c|c|c}
\mathrm{x} & \mathrm{P}_{\mathrm{i}} & \mathrm{P}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}} & \mathrm{P}_1 \mathrm{X}_{\mathrm{i}}{ }^2 \\
-1 & \frac{3}{16} & -\frac{3}{16} & \frac{3}{16} \\
0 & \frac{10}{16} & 0 & 0 \\
1 & \frac{3}{16} & \frac{3}{16} & \frac{3}{16} \\
\hline & & \sum \mathrm{P}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}}=0 & \sum \mathrm{P}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}}{ }^2=\frac{3}{8}
\end{array}$$</p>
<p>$$\begin{aligned}
& \therefore \operatorname{var}(\mathrm{x})=\sum \mathrm{P}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}}^2-\left(\sum \mathrm{P}_{\mathrm{i}} X_{\mathrm{i}}\right)^2 \\
& =\frac{3}{8}-0=\frac{3}{8}
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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