Let the system of equations
x + 5y - z = 1
4x + 3y - 3z = 7
24x + y + λz = μ
λ, μ ∈ ℝ, have infinitely many solutions. Then the number of the solutions of this system,
if x, y, z are integers and satisfy 7 ≤ x + y + z ≤ 77, is :
Solution
<p>$$\begin{aligned}
&\text { For infinitely many solution }\\
&\begin{aligned}
& \Delta=0 \\
& \left|\begin{array}{ccc}
1 & 5 & -1 \\
4 & 3 & -3 \\
24 & 1 & \lambda
\end{array}\right|=0 \\
& \Rightarrow 1(3 \lambda+3)-5(4 \lambda+72)-1(4-72)=0 \\
& \Rightarrow-17 \lambda+3-4 \times 72-4=0 \\
& \Rightarrow 17 \lambda=-289 \\
& \Rightarrow \lambda=-17 \\
& \Delta 1=0
\end{aligned}
\end{aligned}$$</p>
<p>$$\begin{aligned}
& \Rightarrow\left|\begin{array}{ccc}
1 & 5 & -1 \\
7 & 3 & -3 \\
\mu & 1 & -17
\end{array}\right|=0 \\
& \Rightarrow 1(-51+3)-5(-119+3 \mu)-1(7-3 \mu)=0 \\
& \Rightarrow-48+595-15 \mu-7+3 \mu=0 \\
& \Rightarrow 12 \mu=540 \\
& \mu=45 \\
& x+5 y-z=1 \\
& 4 x+3 y-3 z=7 \\
& 24 x+y-17 z=45 \\
& \text { Let } z=1 \\
& x+5 y=1+\lambda] \times 4 \\
& 4 x+3 y=7+3 \lambda
\end{aligned}$$</p>
<p>$\frac{\underset{-}{4 \mathrm{x}}+20 \mathrm{y}=\underset{-}{4+4 \lambda}}{-17 \mathrm{y}=3-\lambda}$</p>
<p>$$\begin{aligned}
\begin{aligned}
\mathrm{y} & =\frac{\lambda-3}{17}, \mathrm{x}=1+\lambda-\frac{5 \lambda-15}{17} \\
& =\frac{32-12 \lambda}{17} \\
7 & \leq \frac{\lambda-3}{17}+\frac{32+12 \lambda}{17}+\lambda \leq 77 \\
7 & \leq \frac{30 \lambda+29}{17} \leq 77 \\
3 & \leq \lambda \leq 42 \\
\lambda & =3,20,37
\end{aligned}
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
This question is part of PrepWiser's free JEE Main question bank. 274 more solved questions on Matrices and Determinants are available — start with the harder ones if your accuracy is >70%.