Medium INTEGER +4 / -1 PYQ · JEE Mains 2022

If the system of linear equations
$2x - 3y = \gamma + 5$,
$\alpha x + 5y = \beta + 1$, where $\alpha$, $\beta$, $\gamma$ $\in$ R has infinitely many solutions then the value
of | 9$\alpha$ + 3$\beta$ + 5$\gamma$ | is equal to ____________.

Answer (integer) 58

Solution

<p>If 2x $-$ 3y = $\gamma$ + 5 and $\alpha$x + 5y = $\beta$ + 1 have infinitely many solutions then</p> <p>${2 \over \alpha } = {{ - 3} \over 5} = {{\gamma + 5} \over {\beta + 1}}$</p> <p>$\Rightarrow \alpha = - {{10} \over 3}$ and $3\beta + 5\gamma = - 28$</p> <p>So $|9\alpha + 3\beta + 5\gamma | = | - 30 - 28| = 58$</p>

About this question

Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations

This question is part of PrepWiser's free JEE Main question bank. 274 more solved questions on Matrices and Determinants are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →