If the system of linear equations
$2x - 3y = \gamma + 5$,
$\alpha x + 5y = \beta + 1$, where $\alpha$, $\beta$, $\gamma$ $\in$ R has infinitely many solutions then the value
of | 9$\alpha$ + 3$\beta$ + 5$\gamma$ | is equal to ____________.
Answer (integer)
58
Solution
<p>If 2x $-$ 3y = $\gamma$ + 5 and $\alpha$x + 5y = $\beta$ + 1 have infinitely many solutions then</p>
<p>${2 \over \alpha } = {{ - 3} \over 5} = {{\gamma + 5} \over {\beta + 1}}$</p>
<p>$\Rightarrow \alpha = - {{10} \over 3}$ and $3\beta + 5\gamma = - 28$</p>
<p>So $|9\alpha + 3\beta + 5\gamma | = | - 30 - 28| = 58$</p>
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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