If x, y, z are in arithmetic progression with common difference d, x $\ne$ 3d, and the determinant of the matrix $$\left[ {\matrix{ 3 & {4\sqrt 2 } & x \cr 4 & {5\sqrt 2 } & y \cr 5 & k & z \cr } } \right]$$ is zero, then the value of k2 is :
Solution
$$\left| {\matrix{
3 & {4\sqrt 2 } & x \cr
4 & {5\sqrt 2 } & y \cr
5 & k & z \cr
} } \right| = 0$$<br><br>${R_1} \to {R_1} + {R_3} - 2{R_2}$<br><br>$\Rightarrow$ $$\left| {\matrix{
0 & {4\sqrt 2 - k - 10\sqrt 2 } & 0 \cr
4 & {5\sqrt 2 } & y \cr
5 & k & z \cr
} } \right| = 0$$ { $\because$ 2y = x + z}<br><br>$\Rightarrow (k - 6\sqrt 2 )(4z - 5y) = 0$<br><br>$\Rightarrow$ k = $6\sqrt 2$ or 4z = 5y (Not possible $\because$ x, y, z in A.P.)<br><br>So, k<sup>2</sup> = 72<br><br>$\therefore$ Option (A)
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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