Let $A = \left( {\matrix{ 2 & { - 2} \cr 1 & { - 1} \cr } } \right)$ and $B = \left( {\matrix{ { - 1} & 2 \cr { - 1} & 2 \cr } } \right)$. Then the number of elements in the set {(n, m) : n, m $\in$ {1, 2, .........., 10} and nAn + mBm = I} is ____________.
Answer (integer)
1
Solution
<p>$${A^2} = \left[ {\matrix{
2 & { - 2} \cr
1 & { - 1} \cr
} } \right]\left[ {\matrix{
2 & { - 2} \cr
1 & { - 1} \cr
} } \right] = \left[ {\matrix{
2 & { - 2} \cr
1 & { - 1} \cr
} } \right] = A$$</p>
<p>$\Rightarrow {A^K} = A,\,K \in I$</p>
<p>$${B^2} = \left[ {\matrix{
{ - 1} & 2 \cr
{ - 1} & 2 \cr
} } \right]\left[ {\matrix{
{ - 1} & 2 \cr
{ - 1} & 2 \cr
} } \right] = \left[ {\matrix{
{ - 1} & 2 \cr
{ - 1} & 2 \cr
} } \right] = B$$</p>
<p>So, ${B^K} = B,\,K \in I$</p>
<p>$n{A^n} + m{B^m} = nA + mB$</p>
<p>$$ = \left[ {\matrix{
{2n - 2n} \cr
{n - n} \cr
} } \right] + \left[ {\matrix{
{ - m} & {2m} \cr
{ - m} & {2m} \cr
} } \right]$$</p>
<p>$= \left[ {\matrix{
1 & 0 \cr
0 & 1 \cr
} } \right]$</p>
<p>So, $2n - m = 1,\, - n + m = 0,\,2m - n = 1$</p>
<p>So, $(m,n) = (1,1)$</p>
About this question
Subject: Mathematics · Chapter: Matrices and Determinants · Topic: Types of Matrices and Operations
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