Medium MCQ +4 / -1 PYQ · JEE Mains 2022

The domain of the function $$f(x)=\sin ^{-1}\left[2 x^{2}-3\right]+\log _{2}\left(\log _{\frac{1}{2}}\left(x^{2}-5 x+5\right)\right)$$, where [t] is the greatest integer function, is :

  1. A $\left(-\sqrt{\frac{5}{2}}, \frac{5-\sqrt{5}}{2}\right)$
  2. B $\left(\frac{5-\sqrt{5}}{2}, \frac{5+\sqrt{5}}{2}\right)$
  3. C $\left(1, \frac{5-\sqrt{5}}{2}\right)$ Correct answer
  4. D $\left[1, \frac{5+\sqrt{5}}{2}\right)$

Solution

<p>$- 1 \le 2{x^2} - 3 < 2$</p> <p>or $2 \le 2{x^2} < 5$</p> <p>or $1 \le {x^2} < {5 \over 2}$</p> <p>$$x \in \left( { - \sqrt {{5 \over 2}} , - 1} \right] \cup \left[ {1,\sqrt {{5 \over 2}} } \right)$$</p> <p>${\log _{{1 \over 2}}}({x^2} - 5x + 5) > 0$</p> <p>$0 < {x^2} - 5x + 5 < 1$</p> <p>${x^2} - 5x + 5 > 0$ & ${x^2} - 5x + 4 < 0$</p> <p>$$x \in \left( { - \infty ,{{5 - \sqrt 5 } \over 2}} \right) \cup \left( {{{5 + \sqrt 5 } \over 2},\infty } \right)$$</p> <p>& $x \in ( - \infty ,1) \cup (4,\infty )$</p> <p>Taking intersection</p> <p>$x \in \left( {1,{{5 - \sqrt 5 } \over 2}} \right)$</p>

About this question

Subject: Mathematics · Chapter: Inverse Trigonometric Functions · Topic: Domain and Range

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