Medium MCQ +4 / -1 PYQ · JEE Mains 2021

$${\cos ^{ - 1}}(\cos ( - 5)) + {\sin ^{ - 1}}(\sin (6)) - {\tan ^{ - 1}}(\tan (12))$$ is equal to :

(The inverse trigonometric functions take the principal values)

  1. A 3$\pi$ $-$ 11
  2. B 4$\pi$ $-$ 9
  3. C 4$\pi$ $-$ 11 Correct answer
  4. D 3$\pi$ + 1

Solution

$${\cos ^{ - 1}}(\cos ( - 5)) + {\sin ^{ - 1}}(\sin (6)) - {\tan ^{ - 1}}(\tan (12))$$<br><br>$= (2\pi - 5) + (6 - 2\pi ) - (12 - 4\pi )$<br><br>$= 4\pi - 11$.

About this question

Subject: Mathematics · Chapter: Inverse Trigonometric Functions · Topic: Domain and Range

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