Medium MCQ +4 / -1 PYQ · JEE Mains 2024

Suppose $$f(x)=\frac{\left(2^x+2^{-x}\right) \tan x \sqrt{\tan ^{-1}\left(x^2-x+1\right)}}{\left(7 x^2+3 x+1\right)^3}$$. Then the value of $f^{\prime}(0)$ is equal to

  1. A $\pi$
  2. B $\sqrt{\pi}$ Correct answer
  3. C 0
  4. D $\frac{\pi}{2}$

Solution

<p>$$\begin{aligned} & f^{\prime}(0)=\lim _{h \rightarrow 0} \frac{f(h)-f(0)}{h} \\ & =\lim _{h \rightarrow 0} \frac{\left(2^h+2^{-h}\right) \tan h \sqrt{\tan ^{-1}\left(h^2-h+1\right)}-0}{\left(7 h^2+3 h+1\right)^3 h} \\ & =\sqrt{\pi} \end{aligned}$$</p>

About this question

Subject: Mathematics · Chapter: Differentiation · Topic: Derivatives of Standard Functions

This question is part of PrepWiser's free JEE Main question bank. 55 more solved questions on Differentiation are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →