The differential equation of the family of circles passing through the points $(0,2)$ and $(0,-2)$ is :
Solution
<p>Family of circles passing through the points (0, 2) and (0, $-$2)</p>
<p>${x^2} + (y - 2)(y + 2) + \lambda x = 0,\,\lambda \in R$</p>
<p>${x^2} + {y^2} + \lambda x - 4 = 0$ ...... (1)</p>
<p>Differentiate w.r.t x</p>
<p>$2x + 2y{{dy} \over {dx}} + \lambda = 0$ ....... (2)</p>
<p>Using (1) and (2), eliminate $\lambda$</p>
<p>${x^2} + {y^2} - \left( {2x + 2y{{dy} \over {dx}}} \right)x - 4 = 0$</p>
<p>$2xy{{dy} \over {dx}} + {x^2} - {y^2} + 4 = 0$</p>
About this question
Subject: Mathematics · Chapter: Differential Equations · Topic: Order and Degree
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