A differential equation representing the family of parabolas with axis parallel to y-axis and whose length of latus rectum is the distance of the point (2, $-$3) from the line 3x + 4y = 5, is given by :
Solution
Length of latus rectum<br><br>$= {{|3(2) + 4( - 3) - 5|} \over 5} = {{11} \over 5}$<br><br>${(x - h)^2} = {{11} \over 5}(y - k)$<br><br>differentiate w.r.t. 'x' :-<br><br>$2(x - h) = {{11} \over 5}{{dy} \over {dx}}$<br><br>again differentiate<br><br>$2 = {{11} \over 5}{{{d^2}y} \over {d{x^2}}}$<br><br>${{11{d^2}y} \over {d{x^2}}} = 10$
About this question
Subject: Mathematics · Chapter: Differential Equations · Topic: Order and Degree
This question is part of PrepWiser's free JEE Main question bank. 172 more solved questions on Differential Equations are available — start with the harder ones if your accuracy is >70%.