Let $z_1$ and $z_2$ be two complex numbers such that $z_1+z_2=5$ and $z_1^3+z_2^3=20+15 i$ Then, $\left|z_1^4+z_2^4\right|$ equals -
Solution
<p>$$\begin{aligned}
& z_1+z_2=5 \\
& z_1^3+z_2^3=20+15 i \\
& z_1^3+z_2^3=\left(z_1+z_2\right)^3-3 z_1 z_2\left(z_1+z_2\right) \\
& z_1^3+z_2^3=125-3 z_1 \cdot z_2(5) \\
& \Rightarrow 20+15 i=125-15 z_1 z_2 \\
& \Rightarrow 3 z_1 z_2=25-4-3 i \\
& \Rightarrow 3 z_1 z_2=21-3 i \\
& \Rightarrow z_1 \cdot z_2=7-i \\
& \Rightarrow\left(z_1+z_2\right)^2=25 \\
& \Rightarrow z_1^2+z_2^2=25-2(7-i) \\
& \Rightarrow 11+2 i \\
& \left(z_1^2+z_2^2\right)^2=121-4+44 i \\
& \Rightarrow z_1^4+z_2^4+2(7-i)^2=117+44 i \\
& \Rightarrow z_1^4+z_2^4=117+44 i-2(49-1-14 i) \\
& \Rightarrow\left|z_1^4+z_2^4\right|=75
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane
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