Medium MCQ +4 / -1 PYQ · JEE Mains 2023

Let $$S = \left\{ {x:x \in \mathbb{R}\,\mathrm{and}\,{{(\sqrt 3 + \sqrt 2 )}^{{x^2} - 4}} + {{(\sqrt 3 - \sqrt 2 )}^{{x^2} - 4}} = 10} \right\}$$. Then $n(S)$ is equal to

  1. A 6
  2. B 4 Correct answer
  3. C 0
  4. D 2

Solution

Let $(\sqrt{3}+\sqrt{2})^{x^{2}-4}=t$ <br/><br/>$$ \begin{aligned} & t+\frac{1}{t}=10 \\\\ \Rightarrow & t^{2}-10 t+1=0 \\\\ \Rightarrow & t=\frac{10 \pm \sqrt{100-4}}{2}=5 \pm 2 \sqrt{6} \end{aligned} $$ <br/><br/><b>Case-I</b> <br/><br/>$$ \begin{aligned} & t=5+2 \sqrt{6} = (\sqrt{3}+\sqrt{2})^{2} \\\\ \Rightarrow & (\sqrt{3}+\sqrt{2})^{x^{2}-4}=(\sqrt{3}+\sqrt{2})^{2} \\\\ \Rightarrow & x^{2}-4=2 \Rightarrow x^{2}=6 \Rightarrow x=\pm \sqrt{6} \end{aligned} $$ <br/><br/><b>Case-II :</b> <br/><br/>$t=5-2 \sqrt{6}$ = $(\sqrt{3}-\sqrt{2})^{2}$ <br/><br/>$(\sqrt{3}+\sqrt{2})^{x^{2}-4}=(\sqrt{3}-\sqrt{2})^{2}$ <br/><br/>$\Rightarrow\left((\sqrt{3}-\sqrt{2})^{-1}\right)^{x^{2}-4}=(\sqrt{3}-\sqrt{2})^{2}$ <br/><br/>$\Rightarrow 4-x^{2}=2$ <br/><br/>$\Rightarrow x^{2}=2$ <br/><br/>$\Rightarrow x=\pm \sqrt{2}$

About this question

Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane

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