Medium MCQ +4 / -1 PYQ · JEE Mains 2022

Let f(x) be a quadratic polynomial such that f($-$2) + f(3) = 0. If one of the roots of f(x) = 0 is $-$1, then the sum of the roots of f(x) = 0 is equal to :

  1. A ${{11} \over 3}$ Correct answer
  2. B ${{7} \over 3}$
  3. C ${{13} \over 3}$
  4. D ${{14} \over 3}$

Solution

<p>$\because$ x = $-$1 be the roots of f(x) = 0</p> <p>$\therefore$ Let $f(x) = A(x + 1)(x - 1)$ ...... (i)</p> <p>Now, $f( - 2) + f(3) = 0$</p> <p>$\Rightarrow A[ - 1( - 2 - b) + 4(3 - b)] = 0$</p> <p>$b = {{14} \over 3}$</p> <p>$\therefore$ Second root of f(x) = 0 will be ${{14} \over 3}$</p> <p>$\therefore$ Sum of roots $= {{14} \over 3} - 1 = {{11} \over 3}$</p>

About this question

Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane

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