The number of real solutions of the equation, x2 $-$ |x| $-$ 12 = 0 is :
Solution
|x|<sup>2</sup> $-$ |x| $-$ 12 = 0<br><br>$\Rightarrow$ (|x| + 3)(|x| $-$ 4) = 0<br><br>$\Rightarrow$ |x| = 4
<br><br>$\Rightarrow$ x = $\pm$4
About this question
Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane
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