Let z1, z2 be the roots of the equation z2 + az + 12 = 0 and z1, z2 form an equilateral triangle with origin. Then, the value of |a| is :
Answer (integer)
6
Solution
For equilateral triangle with vertices z<sub>1</sub>, z<sub>2</sub> and z<sub>3</sub>,<br><br>$z_1^2 + z_2^2 + z_3^3 = {z_1}{z_2} + {z_2}{z_3} + {z_3}{z_1}$<br><br>Here one vertex z<sub>3</sub> is 0<br><br>$\therefore$ $z_1^2 + z_2^2 = {z_1}{z_2} + 0 + 0$<br><br>Given, z<sub>1</sub>, z<sub>2</sub> are roots of ${z^2} + az + 12 = 0$<br><br>$\therefore$ ${z_1} + {z_2} = - a$<br><br>${z_1}{z_2} = 12$<br><br>$\therefore$ $z_1^2 + z_2^2 + 2{z_1}{z_2} = {z_1}{z_2} + 2{z_1}{z_2}$<br><br>$\Rightarrow {({z_1} + {z_2})^2} = 3{z_1}{z_2}$<br><br>$\Rightarrow {( - a)^2} = 3 \times 12$<br><br>$\Rightarrow {a^2} = 36$<br><br>$\Rightarrow a = \pm 6$<br><br>$\Rightarrow |a|\, = 6$
About this question
Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane
This question is part of PrepWiser's free JEE Main question bank. 223 more solved questions on Complex Numbers and Quadratic Equations are available — start with the harder ones if your accuracy is >70%.