Medium INTEGER +4 / -1 PYQ · JEE Mains 2021

The equation of a circle is Re(z2) + 2(Im(z))2 + 2Re(z) = 0, where z = x + iy. A line which passes through the center of the given circle and the vertex of the parabola, x2 $-$ 6x $-$ y + 13 = 0, has y-intercept equal to ______________.

Answer (integer) 1

Solution

Equation of circle is (x<sup>2</sup> $-$ y<sup>2</sup>) + 2y<sup>2</sup> + 2x = 0<br><br>x<sup>2</sup> + y<sup>2</sup> + 2x = 0<br><br>Centre : ($-$1, 0)<br><br>Parabola : x<sup>2</sup> $-$ 6x $-$ y + 13 = 0<br><br>(x $-$ 3)<sup>2</sup> = y $-$ 4<br><br>Vertex : (3, 4)<br><br>Equation of line $\equiv y - 0 = {{4 - 0} \over {3 + 1}}(x + 1)$<br><br>$y = x + 1$<br><br>y-intercept = 1

About this question

Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane

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