Easy INTEGER +4 / -1

The condition that the roots of ax²+bx+c=0 are reciprocals of each other is $ac = b$ (True/1/False/0).

Answer (integer) 1

Solution

If roots are α and 1/α: product = α·(1/α) = 1 = c/a → c = a. So ac = a², not b. Wait: c/a = 1 → c = a. So the condition is c = a, not ac = b. The answer is 0 (False) or statement is wrong. Actually: α·(1/α) = 1 = c/a → c = a. So the statement "ac = b" is false for reciprocal roots. The correct condition is c = a. The answer is 0 (false).

About this question

Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Roots and Their Properties

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