Medium MCQ +4 / -1 PYQ · JEE Mains 2022

If $z=x+i y$ satisfies $|z|-2=0$ and $|z-i|-|z+5 i|=0$, then :

  1. A $x+2 y-4=0$
  2. B $x^{2}+y-4=0$
  3. C $x+2 y+4=0$ Correct answer
  4. D $x^{2}-y+3=0$

Solution

<p>$|z - i| = |z + 5i|$</p> <p>So, $\mathrm{z}$ lies on ${ \bot ^r}$ bisector of $(0,1)$ and $(0, - 5)$</p> <p>i.e., line $y = - 2$</p> <p>as $|z| = 2$</p> <p>$\Rightarrow z = - 2i$</p> <p>$x = 0$ and $y = - 2$</p> <p>so, $x + 2y + 4 = 0$</p>

About this question

Subject: Mathematics · Chapter: Complex Numbers and Quadratic Equations · Topic: Complex Numbers and Argand Plane

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