Let a point P be such that its distance from the point (5, 0) is thrice the distance of P from the point ($-$5, 0). If the locus of the point P is a circle of radius r, then 4r2 is equal to ________
Answer (integer)
56
Solution
Let P(h, k)<br><br>Given<br><br>PA = 3PB<br><br>PA<sup>2</sup> = 9PB<sup>2</sup><br><br>$\Rightarrow$ (h $-$ 5)<sup>2</sup> + k<sup>2</sup> = 9[(h + 5)<sup>2</sup> + k<sup>2</sup>]<br><br>$\Rightarrow$ 8h<sup>2</sup> + 8k<sup>2</sup> + 100h + 200 = 0<br><br>$\therefore$ Locus<br><br>${x^2} + {y^2} + \left( {{{25} \over 2}} \right)x + 25 = 0$<br><br>$\therefore$ $c \equiv \left( {{{ - 25} \over 4},0} \right)$<br><br>$\therefore$ ${r^2} = {\left( {{{ - 25} \over 4}} \right)^2} - 25$<br><br>$= {{625} \over {16}} - 25$<br><br>$= {{225} \over {16}}$<br><br>$\therefore$ $4{r^2} = 4 \times {{225} \over {16}} = {{225} \over 4} = 56.25$<br><br>After Round of 4r<sup>2</sup> = 56
About this question
Subject: Mathematics · Chapter: Circles · Topic: Equation of a Circle
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