The middle term in the expansion of (x + 1/x)^(2n) is:
Solution
(x+1/x)^(2n) has (2n+1) terms. Middle term = term (n+1) = C(2n,n) x^(2n-2n)/x^n = C(2n,n). Wait: T(r+1) = C(2n,r) x^(2n-r) (1/x)^r = C(2n,r) x^(2n-2r). For r=n: C(2n,n) x^(2n-2n) = C(2n,n). So middle term is C(2n,n) (constant).
About this question
Subject: Mathematics · Chapter: Binomial Theorem · Topic: Middle Term
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