Let f be a twice differentiable function on (1, 6). If f(2) = 8, f’(2) = 5, f’(x) $\ge$ 1 and f''(x) $\ge$ 4, for all x $\in$ (1, 6), then :
Solution
Given, $f'(x) \ge 1$<br><br>$\therefore$ $\int_2^5 {f'(x)} dx\, \ge \,\int_2^5 {dx}$<br><br>$\Rightarrow f(5) - f(2) \ge 3$<br><br>$\Rightarrow f(5) - 8 \ge 3$<br><br>$\Rightarrow f(5) \ge 11$ ...(1)<br><br>Also, $f''(x) \ge 4$<br><br>$\therefore$ $\int_2^5 {f''(x)} dx\, \ge \,\int_2^5 {4dx}$<br><br>$\Rightarrow f'(5) - f'(2) \ge 4(3)$<br><br>$\Rightarrow f'(5) - 5 \ge 12$<br><br>$\Rightarrow f'(5) \ge 17$ ...(2)<br><br>From (1) and (2),<br><br>$f'(5) + f'(5) \ge 11 + 17$<br><br>$\Rightarrow f'(5) + f'(5) \ge 28$
About this question
Subject: Mathematics · Chapter: Application of Derivatives · Topic: Tangents and Normals
This question is part of PrepWiser's free JEE Main question bank. 99 more solved questions on Application of Derivatives are available — start with the harder ones if your accuracy is >70%.