For which of the following curves, the line $x + \sqrt 3 y = 2\sqrt 3$ is the tangent at the point $\left( {{{3\sqrt 3 } \over 2},{1 \over 2}} \right)$?
Solution
Tangent to ${x^2} + 9{y^2} = 9$ at
<br><br>point $\left( {{{3\sqrt 3 } \over 2},{1 \over 2}} \right)$ is $x\left( {{{3\sqrt 3 } \over 2}} \right) + 9y\left( {{1 \over 2}} \right) = 9$<br><br>$3\sqrt 3 x + 9y = 18 \Rightarrow x + \sqrt 3 y = 2\sqrt 3$<br><br>$\Rightarrow$ option (1) is true.
About this question
Subject: Mathematics · Chapter: Application of Derivatives · Topic: Tangents and Normals
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