If $\quad C$ (diamond $) \rightarrow C$ (graphite) $+X \mathrm{~kJ} \mathrm{~mol}^{-1}$
C (diamond) $+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Y} \mathrm{kJ} \mathrm{mol}{ }^{-1}$
C (graphite) $+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Z} \mathrm{kJ} \mathrm{mol}^{-1}$
at constant temperature. Then
Solution
<p>Given,</p>
<p>$${C_{(diamond)}}\buildrel {} \over
\longrightarrow {C_{(graphite)}} + X\,kJ\,mo{l^{ - 1}}$$ ............ (1)</p>
<p>$${C_{(diamond)}} + {O_2}(g)\buildrel {} \over
\longrightarrow C{O_2}(g) + Y\,kJ\,mo{l^{ - 1}}$$ ............. (2)</p>
<p>$${C_{(graphite)}} + {O_2}(g)\buildrel {} \over
\longrightarrow C{O_2}(g) + Z\,kJ\,mo{l^{ - 1}}$$ .............. (3)</p>
<p>Condition for temperature : constant</p>
<p>Hess's law is applied here. (Hess's law of constant heat summation)</p>
<p>The given reactions (2) and (3),</p>
<p>(2) - (3) $\Rightarrow$</p>
<p>$${C_{(diamond)}} + {O_2}(g) - \left( {{C_{(graphite)}} + {O_2}(g)} \right)\buildrel {} \over
\longrightarrow C{O_2}(g) + Y - \left( {C{O_2}(g) + Z} \right)$$</p>
<p>$${C_{(diamond)}} + {O_2}(g) - {C_{(grpahite)}} - {O_2}(g)\buildrel {} \over
\longrightarrow C{O_2}(g) + Y - C{O_2}(g) - Z$$</p>
<p>${C_{(diamond)}} - {C_{(graphite)}} \to Y - Z$</p>
<p>${C_{(diamond)}} \to {C_{(graphite)}} + (Y - Z)$ ............. (4)</p>
<p>Comparing (1) and (4),</p>
<p>$X = Y - Z$</p>
<p>So, the correct answer is option (2) $X = Y - Z$</p>
About this question
Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law
This question is part of PrepWiser's free JEE Main question bank. 110 more solved questions on Thermodynamics are available — start with the harder ones if your accuracy is >70%.