The standard entropy change for the reaction
4Fe(s) + 3O2(g) $\to$ 2Fe2O3(s) is $-$550 J K$-$1 at 298 K.
[Given : The standard enthalpy change for the reaction is $-$165 kJ mol$-$1]. The temperature in K at which the reaction attains equilibrium is _____________. (Nearest Integer)
Answer (integer)
300
Solution
$\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}=0$ at equilibrium<br/><br/>
$$
\begin{aligned}
&\Rightarrow-165 \times 10^3-\mathrm{T} \times(-505)=0 \\\\
&\Rightarrow \mathrm{T}=300 \mathrm{~K}
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law
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