A system does 200 J of work and at the same time absorbs 150 J of heat. The magnitude of the change in internal energy is ____________ J. (Nearest integer)
Answer (integer)
50
Solution
w = $-$200 J, q = +150 : $\Delta$U = q + w<br><br>$\Delta$U = 150 $-$ 200 = $-$50 J <br><br>Magnitude = 50 J = |$\Delta$U |
About this question
Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law
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