Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol–1, and 4 kJ mol–1, respectively.
The hydration enthalpy of NaCl is :
Solution
$\Delta$H<sub>sol</sub> = Lattice enthalpy + $\Delta$H<sub>hyd</sub>
<br><br>$\Rightarrow$ 4 = 788 + $\Delta$H<sub>hyd</sub>
<br><br>$\Rightarrow$ $\Delta$H<sub>hyd</sub> = –784 kJ mol<sup>–1</sup>
About this question
Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law
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