For a chemical reaction A + B ⇌ C + D
(${\Delta _r}{H^\Theta }$ = 80 kJ mol$-$1) the entropy change ${\Delta _r}{S^\Theta }$ depends on the temperature T (in K) as ${\Delta _r}{S^\Theta }$ = 2T (J K$-$1mol$-$1).
Minimum temperature at which it will become spontaneous is ___________ K. (Integer)
Answer (integer)
200
Solution
We know, $\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ$
<br><br>For a reaction to be spontaneous
<br>$\Delta G^\circ < 0$
<br><br>$\Rightarrow$ $\Delta H^\circ - T\Delta S^\circ < 0$
<br><br>$\Rightarrow$ $T > {{\Delta H^\circ } \over {\Delta S^\circ }}$
<br><br>$\Rightarrow$ $T > {{80000} \over {2T}}$
<br><br>$\Rightarrow$ 2T<sup>2</sup> > 80000
<br><br>$\Rightarrow$ T<sup>2</sup> > 40000
<br><br>$\Rightarrow$ T > 200
<br><br>The minimum temperature to make it spontaneous is 200 K.
About this question
Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law
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