For a given chemical reaction A $\to$ B at 300 K the free energy change is $-$49.4 kJ mol$-$1 and the enthalpy of reaction is 51.4 kJ mol$-$1. The entropy change of the reaction is _____________ JK$-$1 mol$-$1.
Answer (integer)
336
Solution
$\Delta$G = $-$49.4 kJ/mol<br><br>$\Delta$H = 51.4 kJ/mol<br><br>$\Delta$G = $\Delta$H $-$ T$\Delta$S<br><br>$-$49400 = 51400 $-$ 300$\Delta$S<br><br>$\Delta S = {{ + 100800} \over {300}} = 336$ JK<sup>$-$1</sup> mol<sup>$-$1</sup>
About this question
Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law
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