Easy INTEGER +4 / -1 PYQ · JEE Mains 2021

For a given chemical reaction A $\to$ B at 300 K the free energy change is $-$49.4 kJ mol$-$1 and the enthalpy of reaction is 51.4 kJ mol$-$1. The entropy change of the reaction is _____________ JK$-$1 mol$-$1.

Answer (integer) 336

Solution

$\Delta$G = $-$49.4 kJ/mol<br><br>$\Delta$H = 51.4 kJ/mol<br><br>$\Delta$G = $\Delta$H $-$ T$\Delta$S<br><br>$-$49400 = 51400 $-$ 300$\Delta$S<br><br>$\Delta S = {{ + 100800} \over {300}} = 336$ JK<sup>$-$1</sup> mol<sup>$-$1</sup>

About this question

Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law

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