Easy MCQ +4 / -1 PYQ · JEE Mains 2024

Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following :

  1. A $\mathrm{q}=0, \Delta \mathrm{T}=0, \mathrm{w}=0$ Correct answer
  2. B $\mathrm{q}=0, \Delta \mathrm{T} \neq 0, \mathrm{w}=0$
  3. C $\mathrm{q} \neq 0, \Delta \mathrm{T}=0, \mathrm{w}=0$
  4. D $\mathrm{q}=0, \Delta \mathrm{T}<0, \mathrm{w} \neq 0$

Solution

<p>Let's analyze what happens during a free (or unrestrained) expansion of an ideal gas under adiabatic conditions:</p> <ul> <li>Adiabatic process : By definition, in an adiabatic process, no heat is transferred between the system and its surroundings. Thus, $ q = 0 $.</li> <br/><li>Free expansion : In a free expansion, the gas expands into a vacuum or against zero external pressure. Since work ($ w $) is defined as the product of pressure ($ P $) and volume change ($ \Delta V $), and since the external pressure is zero, we conclude that $ w = 0 $.</li> <br/><li>Temperature change ($ \Delta T $) : Since work is zero and no heat is transferred, the first law of thermodynamics tells us that the change in internal energy ($ \Delta U $) is zero as well. For an ideal gas, internal energy is a function of temperature only; thus, if the internal energy does not change, the temperature does not change. Therefore, $ \Delta T = 0 $.</li> </ul> <p>Based on the above points, the free expansion of an ideal gas under adiabatic conditions is characterized by no heat transfer ($ q = 0 $), no work done ($ w = 0 $), and no change in temperature ($ \Delta T = 0 $). Therefore, the correct option is:</p> <p>Option A : $ q = 0, \Delta T = 0, w = 0 $</p>

About this question

Subject: Chemistry · Chapter: Thermodynamics · Topic: Zeroth and First Law

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