In sulphur estimation, 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is ____________ (Nearest Integer)
(Given : Atomic mass Ba: 137 u, S: 32 u, O: 16 u)
Answer (integer)
42
Solution
$$
\begin{aligned}
\% \text { of sulphur } & =\frac{32}{233} \times \frac{\text { weight of } \mathrm{BaSO}_4 \text { formed }}{\text { weight of organic compound }} \times 100 \\\\
& =\frac{32}{233} \times \frac{1.4439}{0.471} \times 100 \\\\
& =42.10
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
This question is part of PrepWiser's free JEE Main question bank. 163 more solved questions on Some Basic Concepts of Chemistry are available — start with the harder ones if your accuracy is >70%.