Easy INTEGER +4 / -1 PYQ · JEE Mains 2025

Consider the following reaction occurring in the blast furnace:

$$\mathrm{Fe}_3 \mathrm{O}_{4(\mathrm{~s})}+4 \mathrm{CO}_{(\mathrm{g})} \rightarrow 3 \mathrm{Fe}_{(\mathrm{l})}+4 \mathrm{CO}_{2(\mathrm{~g})}$$

' $x$ ' kg of iron is produced when $2.32 \times 10^3 \mathrm{~kg} \mathrm{Fe}_3 \mathrm{O}_4$ and $2.8 \times 10^2 \mathrm{~kg} \mathrm{CO}$ are brought together in the furnace. The value of ' $x$ ' is _________ . (nearest integer)

{Given: molar mass of $\mathrm{Fe}_3 \mathrm{O}_4=232 \mathrm{~g} \mathrm{~mol}^{-1}$

molar mass of $\mathrm{CO}=28 \mathrm{~g} \mathrm{~mol}^{-1}$

molar mass of $\mathrm{Fe}=56 \mathrm{~g} \mathrm{~mol}^{-1}$}

Answer (integer) 420

Solution

<p>moles of $\mathrm{Fe}_3 \mathrm{O}_4=\frac{2.32 \times 10^3 \times 10^3}{232}=10000 \mathrm{~mol}$</p> <p>moles of $\mathrm{CO}=\frac{2.8 \times 10^2 \times 10^3}{28}=10000 \mathrm{~mol}$</p> <p>$$\begin{aligned} & \mathrm{Fe}_3 \mathrm{O}_4+4 \mathrm{CO} \longrightarrow 3 \mathrm{Fe}+4 \mathrm{CO}_2 \\ & 10^4 \mathrm{~mol} \quad 10^4 \mathrm{~mol} \end{aligned}$$</p> <p>CO is L.R.</p> <p>mole of $\mathrm{Fe}=\frac{3}{4} \times 10^4$</p> <p>mass of $\mathrm{Fe}=\frac{3}{4} \times \frac{10^4 \times 56}{1000} \mathrm{~kg}=420 \mathrm{~kg}$</p>

About this question

Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept

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