On complete combustion, $0.492 \mathrm{~g}$ of an organic compound gave $0.792 \mathrm{~g}$ of $\mathrm{CO}_{2}$. The % of carbon in the organic compound is ___________ (Nearest integer)
Answer (integer)
44
Solution
Weight of $\mathrm{C}$ in $0.792 \mathrm{gm} $ $\mathrm{CO}_2$
<br/><br/>$$
\begin{aligned}
& =\frac{12}{44} \times 0.792=0.216 \\\\
& \% \text { of } C \text { in compound }=\frac{0.216}{0.492} \times 100 \\\\
& =43.90 \%
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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