Concentrated nitric acid is labelled as $75 \%$ by mass. The volume in mL of the solution which contains 30 g of nitric acid is ______________.
Given : Density of nitric acid solution is $1.25 \mathrm{~g} / \mathrm{mL}$.
Solution
<p>$\% \mathrm{w} / \mathrm{w}$ of $\mathrm{HNO}_3=75 \%$</p>
<p>means 100 gm of solution containing 75 g of $\mathrm{HNO}_3$</p>
<p>$\&\left(\frac{\mathrm{gm}}{\mathrm{m}_1}\right)_{\text {solution }}=1.25=\frac{100 \mathrm{gm}}{\mathrm{V}}$</p>
<p>$\mathrm{V}_{\mathrm{ml}}$ of 100 gm solution $=\frac{100}{1.25} \mathrm{ml}$</p>
<p>$\because 75 \mathrm{gm}$ of $\mathrm{HNO}_3$ present in $\frac{100}{1.25} \mathrm{ml}$ solution</p>
<p>$\therefore 30 \mathrm{gm}$ of $\mathrm{HNO}_3$ present in</p>
<p>$\frac{100}{1.25 \times 75} \times 30=32 \mathrm{ml} \text { solution }$</p>
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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