The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4.2H2O) in 250 mL of water in mol L$-$1 is x $\times$ 10$-$2. The value of x is _____________. (Nearest integer) [Atomic mass : H : 1.0, C : 12.0, O : 16.0]
Answer (integer)
20
Solution
$[{H_2}{C_2}{O_4}.2{H_2}O] = {{weight/{M_w}} \over {V(L)}}$<br><br>$\Rightarrow x \times {10^{ - 2}} = {{6.3/126} \over {250/1000}}$<br><br>$x = 20$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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