The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is ___________.
Answer (integer)
10
Solution
H<sub>3</sub>PO<sub>2</sub> + NaOH $\to$ NaH<sub>2</sub>PO<sub>2</sub> + H<sub>2</sub>O
<br><br>Using Stoichiometry
<br><br><span style="display: inline-block;vertical-align: middle;">
<div style="text-align: center;border-bottom: 1px solid black;">Moles of H<sub>3</sub>PO<sub>2</sub> reacted</div>
<div style="text-align: center;">1</div>
</span> = <span style="display: inline-block;vertical-align: middle;">
<div style="text-align: center;border-bottom: 1px solid black;">Moles of NaOH reacted</div>
<div style="text-align: center;">1</div></span>
<br><br>$\Rightarrow$ ${{0.1 \times 10} \over 1}$ = 0.1 × V<sub>NaOH</sub>
<br><br>$\Rightarrow$ V<sub>NaOH</sub> = 10 ml
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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