"1 L aqueous solution of H2SO4 contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ___________ $\times$ 103 m mols."

Question

Accepted Answer

"$\mathrm{n}_{\mathrm{H}_2 \mathrm{SO}_4}$ in $\mathrm{Sol}^{\mathrm{n}} \mathrm{A}=50 \%$ of original solution

$=0.01 \mathrm{~m} \mathrm{~mol}$.

$\mathrm{n}_{\mathrm{H}_2 \mathrm{SO}_4}$ in Final solution $=0.01+0.01$

$=0.02 \,\mathrm{m\,mol}$

$=0.00002 \times 10^3 \mathrm{m\,mol}$

The answer 0"

1 L aqueous solution of H₂SO₄ contains 0.02 m mol H₂SO₄. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H₂SO₄ are added. Total m mols of H₂SO₄ in the final solution is ___________ $\times$ 10³ m mols.

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1 L aqueous solution of H2SO4 contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ___________ $\times$ 103 m mols.

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1 L aqueous solution of H₂SO₄ contains 0.02 m mol H₂SO₄. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H₂SO₄ are added. Total m mols of H₂SO₄ in the final solution is ___________ $\times$ 10³ m mols.