Easy INTEGER +4 / -1 PYQ · JEE Mains 2024

A solution of $\mathrm{H}_2 \mathrm{SO}_4$ is $31.4 \% \mathrm{H}_2 \mathrm{SO}_4$ by mass and has a density of $1.25 \mathrm{~g} / \mathrm{mL}$. The molarity of the $\mathrm{H}_2 \mathrm{SO}_4$ solution is _________ $\mathrm{M}$ (nearest integer)

[Given molar mass of $\mathrm{H}_2 \mathrm{SO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1}$]

Answer (integer) 4

Solution

<p>$$\begin{aligned} & M=\frac{n_{\text {solute }}}{V} \times 1000 \\ & =\frac{\left(\frac{31.4}{98}\right)}{\left(\frac{100}{1.25}\right)} \times 1000 \\ & =4.005 \approx 4 \end{aligned}$$</p>

About this question

Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept

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