An average person needs about 10000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol$-$1) needed to meet this energy requirement is ____________ g.
(Use : $\Delta$CH(glucose) = $-$2700 kJ mol$-$1)
Answer (integer)
667
Solution
1 mole glucose give 2700 kJ energy, <br/><br/>so mole of glucose needed for 10<sup>4</sup> kJ energy<br/><br/>= ${{10000} \over {2700}} = 3.703$ moles<br/><br/>Weight of glucose = 3.703 $\times$ 180 g/moles<br/><br/>= 666.666<br/><br/>$\approx$ 667 g<br/><br/>Hence, amount of glucose required is 667 g.
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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