An aqueous KCl solution of density 1.20 g mL$-$1 has a molality of 3.30 mol kg$-$1. The molarity of the solution in mol L$-$1 is ____________ (Nearest integer) [Molar mass of KCl = 74.5]
Answer (integer)
3
Solution
1000 kg solvent has 3.3 moles of KCl<br><br>1000 kg solvent $\to$ 3.3 $\times$ 74.5 gm KCl $\to$ 245.85<br><br>Weight of solution = 1245.85 gm<br><br>Volume of solution = ${{1245.85} \over {1.2}}$ ml<br><br>So molarity = ${{3.3 \times 1.2} \over {1245.85}} \times 1000 = 3.17$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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