The amount of calcium oxide produced on heating 150 kg limestone ( $75 \%$ pure) is _________ kg. (Nearest integer)
Given: Molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$ ) of Ca-40, O-16, C-12
Answer (integer)
63
Solution
<p>$$\begin{aligned}
& \mathrm{CaCO}_3 \rightarrow \mathrm{CaO}+\mathrm{CO}_2 \\
& \text { mass of } \mathrm{CaCO}_3=\frac{150 \times 75}{100}=112.5 \mathrm{~kg} \\
& =112500 \mathrm{~g} \\
& \mathrm{n}_{\mathrm{CaCO}_3}=1125
\end{aligned}$$</p>
<p>$$\begin{aligned}
& \text { So moles of } \mathrm{CaO}=1125 \\
& \qquad \text { mass of } \mathrm{CaO}=\frac{1125 \times 56}{1000}=63 \mathrm{~kg} \\
& \text { Correct answer } \Rightarrow 63
\end{aligned}$$</p>
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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