The mole fraction of glucose (C6H12O6 ) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is _______.
Answer (integer)
47
Solution
Mole fraction of glucose in aqueous solution
= 0.1
<br><br>Let total mole is 1 mol then mole of glucose will be 0.1 and mole of water will be 0.9.
<br><br>So mass % of water = ${{0.9 \times 18} \over {0.1 \times 180 + 0.9 \times 18}}$ $\times$ 100
<br><br>= 47.37 $\simeq$ 47
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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