The volume (in mL) of 0.125 M AgNO3 required to quantitatively precipitate chloride ions in 0.3 g of
[Co(NH3)6]Cl3 is ________.
M[Co(NH3)6Cl3] = 267.46 g/mol
MAgNO3 = 169.87 g/mol
Answer (integer)
26
Solution
[Co(NH<sub>3</sub>)<sub>6</sub>]Cl<sub>3</sub> + 3AgNO<sub>3</sub> $\to$ 3AgCl
<br><br><span style="display: inline-block;vertical-align: middle;">
<div style="text-align: center;border-bottom: 1px solid black;">Mole of [Co(NH<sub>3</sub>)<sub>6</sub>]Cl<sub>3</sub></div>
<div style="text-align: center;">1</div>
</span> = <span style="display: inline-block;vertical-align: middle;">
<div style="text-align: center;border-bottom: 1px solid black;">Mole of AgNO<sub>3</sub></div>
<div style="text-align: center;">3</div>
</span>
<br><br>$\Rightarrow$ ${{0.3} \over {267.46}} = {{0.125 \times v \times {{10}^{ - 3}}} \over 3}$
<br><br>$\Rightarrow$ v = 26.92 ml
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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